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209=2w^2-3w
We move all terms to the left:
209-(2w^2-3w)=0
We get rid of parentheses
-2w^2+3w+209=0
a = -2; b = 3; c = +209;
Δ = b2-4ac
Δ = 32-4·(-2)·209
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-41}{2*-2}=\frac{-44}{-4} =+11 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+41}{2*-2}=\frac{38}{-4} =-9+1/2 $
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